8x-4[5-3(x+1)]=0

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Solution for 8x-4[5-3(x+1)]=0 equation:


Simplifying
8x + -4[5 + -3(x + 1)] = 0

Reorder the terms:
8x + -4[5 + -3(1 + x)] = 0
8x + -4[5 + (1 * -3 + x * -3)] = 0
8x + -4[5 + (-3 + -3x)] = 0

Combine like terms: 5 + -3 = 2
8x + -4[2 + -3x] = 0
8x + [2 * -4 + -3x * -4] = 0
8x + [-8 + 12x] = 0

Reorder the terms:
-8 + 8x + 12x = 0

Combine like terms: 8x + 12x = 20x
-8 + 20x = 0

Solving
-8 + 20x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 20x = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 20x = 0 + 8
20x = 0 + 8

Combine like terms: 0 + 8 = 8
20x = 8

Divide each side by '20'.
x = 0.4

Simplifying
x = 0.4

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